The total no of orbital of the central atom of XeF2 PARTICIPATING IN HYBRIDISATION?

Dear  prashant ,

When you draw out the Lewis structure for XeF2, with Xe having three lone pairs and two bonds with each F, with a total steric number of 5. This also means that there are five orbitals present. The only possible hybridization with five orbitals is dsp3 hybridization. (1d+1s+3p=5dsp3)
If you think in terms of VSEPR geometry, XeF2 has a trigonal bipyramidal design. Trigonal Bipyramidals have dsp3 hybridization.

so it has 5 orbitals in hybridisation.

 Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..

Askiitians Expert

Ajit Singh Verma IITD