Calculate the hardness of a water sample, whose 20 ml required 30 ml EDTA. 10 ml of standard calcium chloride solution, whose strength is equivalent to 300 mg of CaCO3 per 200 ml required 20 ml of the same EDTA solution.

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Vaastav · Answer

1000 ml standard solution has 15,00 mg of CaCO3 given in question, Therefore, 1 ml of standard water has 15,00/1000 = 1.5 mg of CaCO3 So 10 ml of EDTA solution contains,15 mg of CaCO3 equivalent 1ml of EDTA contains 15 / 10 = 1.5 mg of CaCo3 equivalent 100 ml of sample with 30 ml of EDTA solution contains 30 * 1.5 is 45 mg of CaCO3 Therefore , 1000 ml of water has 450 mg of CaCO3 By definition, temporary hardness of water is amount of impurity in 1000 ml of water and therefore hardness of water comes out to be 450 mg per litre.

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Calculate the hardness of a water sample, whose 20 ml required 30 ml EDTA. 10 ml of standard calcium chloride solution, whose strength is equivalent to 300 mg of CaCO3 per 200 ml required 20 ml of the same EDTA solution.

Calculate the hardness of a water sample, whose 20 ml required 30 ml EDTA. 10 ml of standard calcium chloride solution, whose strength is equivalent to 300 mg of CaCO3 per 200 ml required 20 ml of the same EDTA solution.

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Calculate the hardness of a water sample, whose 20 ml required 30 ml EDTA. 10 ml of standard calcium chloride solution, whose strength is equivalent to 300 mg of CaCO3 per 200 ml required 20 ml of the same EDTA solution.

Calculate the hardness of a water sample, whose 20 ml required 30 ml EDTA. 10 ml of standard calcium chloride solution, whose strength is equivalent to 300 mg of CaCO3 per 200 ml required 20 ml of the same EDTA solution.

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