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A particle begins to move with a tangential acceleration of constant magnitude 0.6 m/s^2 in a circular path. If it slips when its total acceleration becomes 1 m/s. Find the angle through which it would have turned before it starts to slip.
A particle begins to move with a tangential acceleration of constant magnitude 0.6 m/s^2 in a circular path. If it slips when its total acceleration becomes 1 m/s. Find the angle through which it would have turned before it starts to slip.

```
4 years ago

HARSHDEEP SINGH CHHABRA
15 Points
```							When net acceleration=1Tangential acceleration=0.6 and centripetal =0.8Now w^2R=0.8 So w^2=0.8/r Tagential acceleration=0.6=rα So α=0.6/rNow as acceleration is constant, we can usew^2=2α theta You can get theta from here which equals 2/3rad
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions