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A horizontal tube of small thickness having inner raius r=R/2 is placed in gravity free space. Magnetic field of strength B iis present perpendicular to plane of circular tube. A charged particle(q,m) inside the tube is given tangential velocity vo= qbr/m. Find the work done by friction long after motion.(inner surface of tube is rough)

Lakshita , 9 Years ago
Grade 12
anser 1 Answers
GAGANDEEP SINGH
Apply work energy theorem. Apart from friction no other force will do work since they are perpendicular to particle`s motion. And change in KE is -0.5mv^2. And this is the answer.
Last Activity: 9 Years ago
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