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Grade 12Magnetism

A verical circular coil of radius 0.1 m and of 10 turns carries a steady current .When the plane of the coil is normal to the magnetic meridian, a neutral point is observed at the centre of the coil.if BH=horizontal component of earth's magnetic field =0.314×10^-4 T then find the current flowing through the coil.

Indranil sen

6 Years agoGrade 12

2 Answers

Arun

6 Years ago

Dear student

As we know

B = mu * N* i /2r

hence

I = 2 B* r / 2 N* mu

Now put the value and you will get the amswer 0.5 pi

Hope it helps

Vikas TU

6 Years ago

Dear student
At neutral point
Magnetic field become opposite and equal to some other magnetic field ,
Other magnetic field = Horizontal component of earth magnetic field.
Bh = magnetic field at centre of crcular coil = (μ0/4π)*2pie nI /r
I = (μ0/4π)* rBh /2pie*n
(10^7*0.1*0.314*10^-4)/ (2*3.14*10) = 0.5A
Hope this helps

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