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A verical circular coil of radius 0.1 m and of 10 turns carries a steady current .When the plane of the coil is normal to the magnetic meridian, a neutral point is observed at the centre of the coil.if BH=horizontal component of earth's magnetic field =0.314×10^-4 T then find the current flowing through the coil.

A verical circular coil of radius 0.1 m and of 10 turns carries a steady current  .When the plane of the coil is normal  to the magnetic meridian, a neutral  point  is observed at the centre of the coil.if    BH=horizontal component of earth's magnetic field =0.314×10^-4 T then find the current  flowing  through the coil.

Grade:12

2 Answers

Arun
25763 Points
one year ago
Dear student
As we know
B = mu * N* i /2r
hence
I = 2 B* r / 2 N* mu
Now put the value and you will get the amswer 0.5 pi
Hope it helps
Vikas TU
14149 Points
one year ago
Dear student 
At neutral point 
Magnetic field become opposite and equal to some other magnetic field , 
Other magnetic field = Horizontal component of earth magnetic field.
Bh = magnetic field at centre of crcular coil = (μ0/4π)*2pie nI /r 
I = (μ0/4π)* rBh /2pie*n 
(10^7*0.1*0.314*10^-4)/ (2*3.14*10) = 0.5A 
Hope this helps  
 

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