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a ball is thrown  verticaly up with a velocity u from top of a tower .if it strikes the ground with a velocity of 3u the time taken by the ball to reach the ground is

3 years ago

Dhiraj Jain
19 Points
t=g/2u As we know that s= v-u/t therefore we can get value of s which is equal to height of building by using formula v^2 -u^2 = 2as  acceleration is g now by putting all values we will get result t is equal to g/2u  . Hope it would be helpful for others.

3 years ago
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