Grade 12General Physics
Convert 1 newton into dyne using method of dimension
Convert 1 newton into dyne using method of dimension
2 Answers
Yuvraj Singh
Convert 1 newton into dyne using method of dimension
Ans:
the dimensional formula of ForceF=[M1L1T−2]
Soa=1,b=1,c=−2
Now because Newton is in m.k.s system, we have
M1=1kg
L1=1m
T1=1s
M2=1g
L2=1cm
T2=1s
n1=1Newton
n2=?
Using the formula
n2=n1[M1/M2]a[L1/L2]b[T1/T2]c
n2=1[1kg/1g]1[1m/1cm]1[1s/1s]−2
n2=1[1000g/1g]1[100cm/1cm]1×1
n2=1000×100=100000=105dynes
Ans:
the dimensional formula of ForceF=[M1L1T−2]
Soa=1,b=1,c=−2
Now because Newton is in m.k.s system, we have
M1=1kg
L1=1m
T1=1s
M2=1g
L2=1cm
T2=1s
n1=1Newton
n2=?
Using the formula
n2=n1[M1/M2]a[L1/L2]b[T1/T2]c
n2=1[1kg/1g]1[1m/1cm]1[1s/1s]−2
n2=1[1000g/1g]1[100cm/1cm]1×1
n2=1000×100=100000=105dynes
Yuvraj Singh
the dimensional formula of ForceF=[M1L1T−2]
Soa=1,b=1,c=−2
Now because Newton is in m.k.s system, we have
M1=1kg
L1=1m
T1=1s
M2=1g
L2=1cm
T2=1s
n1=1Newton
n2=?
Using the formula
n2=n1[M1/M2]a[L1/L2]b[T1/T2]c
n2=1[1kg/1g]1[1m/1cm]1[1s/1s]−2
n2=1[1000g/1g]1[100cm/1cm]1×1
n2=1000×100=100000=105dynes
Soa=1,b=1,c=−2
Now because Newton is in m.k.s system, we have
M1=1kg
L1=1m
T1=1s
M2=1g
L2=1cm
T2=1s
n1=1Newton
n2=?
Using the formula
n2=n1[M1/M2]a[L1/L2]b[T1/T2]c
n2=1[1kg/1g]1[1m/1cm]1[1s/1s]−2
n2=1[1000g/1g]1[100cm/1cm]1×1
n2=1000×100=100000=105dynes
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