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A monochromatic beam of wavelength 6000A and intensity 10mwcm-2 fall on surface the no of photons striking the surface per second per cm2 are
Dear student I = (n/tA )*(hc/Lambda)........1no of electrons emitted = 1/100 * (nt/A)Intensity = 10Put all values in equaton 1 (n/tA) = 3.01 * 10^19 So, no of photons incident per unit time per unit area = 0.01 8 (n/tA) = 3 * 10^17 Hope this helps
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