A monochromatic beam of wavelength 6000A and intensity 10mwcm-2 fall on surface the no of photons striking the surface per second per cm2 are

Question

Vikas TU · Answer

Dear student
I = (n/tA )*(hc/Lambda)........1
no of electrons emitted = 1/100 * (nt/A)
Intensity = 10
Put all values in equaton 1
(n/tA) = 3.01 * 10^19
So, no of photons incident per unit time per unit area
= 0.01 8 (n/tA)
= 3 * 10^17
Hope this helps

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A monochromatic beam of wavelength 6000A and intensity 10mwcm-2 fall on surface the no of photons striking the surface per second per cm2 are

A monochromatic beam of wavelength 6000A and intensity 10mwcm-2 fall on surface the no of photons striking the surface per second per cm2 are

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