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# In young's double silt experiment the distance between the silt is 1.2mm and the screen is 0.75m from the silts. If the distance of the 5th fringe from the central fringe on the screen is 1.8mm. Calculate the wavelength of light used. What will be the distance of the 5th fringe from the center of the screen?

6 months ago

Arun
24736 Points

As we learnt in

Young Double Slit Experiment -

- wherein

$y=\Delta x\cdot \left ( \frac{D}{d} \right )$

$y=$ Distance of a point on screen from central maxima

$\Delta x=$ Path difference at that point

Ref y be the distance from the central maximum to the point where the bright fringes due to both the wavelength coincides

For $\lambda_{1}$,  $y=\frac{m\lambda_{1}D}{d}$

for  $\lambda_{2}$,   $y=\frac{n\lambda_{2}D}{d}$

$\therefore\ \; m \lambda_{1}=n\lambda_{2}$

6 months ago
Vikas TU
12135 Points

Dear student
Good Luck
6 months ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions