Two sides of a triangle are given by the roots of the equation x^2-5x+6=0 and angle between the sides is 60°. Then the perimeter of the triangle is

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Arun · Answer

Dear student On Solving quadratic equations, we get x = 3 and 2 Hence sides are 3 and 2 Now Cos 60 = 3² + 2² - c² /(2*3*2) 1/2 = 13 -c² /12 6 = 13 -c² c² = 7 Hence c = √7 Now perimeter = 2 +3 + √7 = 5 + √7

Vikas TU · Answer

Dear student https://www.askiitians.com/forums/Trigonometry/two-sides-of-a-triangle-are-given-by-the-roots-of_260218.htm Good Luck Cheers

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Two sides of a triangle are given by the roots of the equation x^2-5x+6=0 and angle between the sides is 60°. Then the perimeter of the triangle is

Two sides of a triangle are given by the roots of the equation x^2-5x+6=0 and angle between the sides is 60°. Then the perimeter of the triangle is

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Two sides of a triangle are given by the roots of the equation x^2-5x+6=0 and angle between the sides is 60°. Then the perimeter of the triangle is

Two sides of a triangle are given by the roots of the equation x^2-5x+6=0 and angle between the sides is 60°. Then the perimeter of the triangle is

2 Answers

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