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Two sides of a triangle are given by the roots of the equation x^2-5x+6=0 and angle between the sides is 60°.then the perimeter of the triangle is

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7 months ago

```							On Solving quadratic equations, we get x = 3 and 2 Hence sides are 3 and 2 Now Cos 60 = 3² + 2² - c² /(2*3*2) 1/2 = 13 -c² /12 6 = 13 -c² c² = 7Hence c = √7 Now perimeter = 2 +3 + √7 = 5 + √7 Hope it helps Thanks and regards
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7 months ago
```							Dear student x^2-5x+6=0 x^2-2x-3x+6=0x(x-2)-3(x-2)=0 (x-3)(x-2)=0x=2,3Let the sides of the triangle be named as a,b,c where a=2, b=3 and c=?To the find the value of c: Given that angle between two sides is 60° By using cosine rule CosC=a^2+b^2-c^2/2ab 1/2=4+9-c^3/2*2*3 c=7^1/2then perimeter of the triangle ABC =a+b+c=2+3+7^1/2 =5+7^1/2
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6 months ago
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