Find the radius of the circle in which a central angle of 60° intercepts an arc of length 37.4 cm (use π = 22/7).

360 angle means 2pi r is length of arc

so for 60 angle the length of arc is pi  r/3 which is equal to 37.4 so

if we do this calculation we get r as some thing which is the answer

 

Area of sector=lr/2,

wher, l=length of arc and r= radius of circle

Area of sector=(x°/360°)*πr²

where x°=angle made by the two radii with centre of the circle

i.e; lr/2=(x°/360°)πr²

      l/2=(x°/360°)πr

     37.4/2=(60/360)*(22/7)r 

     18.7=(1/6)(22/7)r

     18.7*6*7/22=r

      785.4/22=r

     r=35.7cm

Therefore radius of the circle is 35.7cm

 

 

 

 

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Thank You.

 

Let the radius be r
(2*22*r*60)/(7*360) = 37.4 cm
[Since, central angle is 60, we multiply 2*(22/7)*r by 60/360]
=> r = (37.4*7*360)/(2*22*60) = 35.7
So, the radius of the circle is 35.7 cm.