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secA-tanA = K, then sinA = ?sin x + sin y = a ; cos x + cos y = b, then tan(x+y/2) = ?(ans in terms of a and b)

Shubham Modi , 8 Years ago
Grade 11
anser 2 Answers
Subhiksha

Last Activity: 8 Years ago

secA- Tan A =K
1-sinA/ ( 1- sin2A)½ =k
k2= 1- sin A / 1+ sin A
By applying componendo and dividendo,
sinA = 1- k2/1+k2
 
sinx + siny= 2cos(x-y/2)sin(x+y/2) =a
Cosx+ Cosy= 2cos(x-y/2)cos(x+y/2) = b
 
On dividing both the above equations,
= a/b tan(x+y/2)
 

Subhiksha

Last Activity: 8 Years ago

rewrite the last equationasTan (

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