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Grade: 9 

                        
solve plz...sin 4 θ + sin 2 θ =1 and show now, tan 2 θ = 1+sin 2 θ

							
solve plz...sin4θ + sin2θ =1 and show now, tan2θ = 1+sin2θ
4 months ago

Answers : (1)

adilakshmigogada 27
101 Points 
							
 
Given,
sin4θ+sin2θ=1
or, sin4θ=1−sin2θ
or, sin4θ=cos2θ.......(1).
Now,
tan4θ−tan2θ
 
=cos4θsin4θ​−tan2θ
 
=cos2θ1​−tan2θ [ Using (1)]
 
=sec2θ−tan2θ
=1.
3 months ago
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