Grade 9Trigonometry
solve plz...sin4θ + sin2θ =1 and show now, tan2θ = 1+sin2θ
solve plz...sin4θ + sin2θ =1 and show now, tan2θ = 1+sin2θ
1 Answer
adilakshmigogada 27
Given,
sin4θ+sin2θ=1
or, sin4θ=1−sin2θ
or, sin4θ=cos2θ.......(1).
Now,
tan4θ−tan2θ
=cos4θsin4θ−tan2θ
=cos2θ1−tan2θ [ Using (1)]
=sec2θ−tan2θ
=1.
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