solve plz...sin 4 θ + sin 2 θ =1 and show now, tan 2 θ = 1+sin 2 θ

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adilakshmigogada 27 · Answer

Given, sin 4 θ + sin 2 θ = 1 or, sin 4 θ = 1 − sin 2 θ or, sin 4 θ = cos 2 θ .......(1). Now, tan 4 θ − tan 2 θ = cos 4 θ sin 4 θ ​ − tan 2 θ = cos 2 θ 1 ​ − tan 2 θ [ Using (1)] = sec 2 θ − tan 2 θ = 1 .

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solve plz...sin 4 θ + sin 2 θ =1 and show now, tan 2 θ = 1+sin 2 θ

solve plz...sin⁴θ + sin²θ =1 and show now, tan²θ = 1+sin²θ

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solve plz...sin 4 θ + sin 2 θ =1 and show now, tan 2 θ = 1+sin 2 θ

solve plz...sin4θ + sin2θ =1 and show now, tan2θ = 1+sin2θ

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solve plz...sin⁴θ + sin²θ =1 and show now, tan²θ = 1+sin²θ