In a ?ABC, if cos A / a = cos B / b = cos C / c and the side a = 2, then area of the triangle is

Question

bharat bajaj · Answer

cos A / a = cos B / b = cos C / c
cos A / (2R sin A) = cos B / (2R sin B) = cos C / (2R sin C)
cot A = cot B = cot C
A = B = C
?ABC is equilateral.
Area = Formula for area of an equilateral triangle

=

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Bharat Bajaj

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In a ?ABC, if cos A / a = cos B / b = cos C / c and the side a = 2, then area of the triangle is

In a ?ABC, if cos A / a = cos B / b = cos C / c and the side a = 2, then area of the triangle is

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