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In a ?ABC, if cos A / a = cos B / b = cos C / c and the side a = 2, then area of the triangle is
cos A / a = cos B / b = cos C / ccos A / (2R sin A) = cos B / (2R sin B) = cos C / (2R sin C)cot A = cot B = cot CA = B = C?ABC is equilateral.Area ==ThanksBharat Bajajaskiitians facultyIIT Delhi
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