In a ?ABC, if cos A / a = cos B / b = cos C / c and the side a = 2, then area of the triangle is
In a ?ABC, if cos A / a = cos B / b = cos C / c and the side a = 2, then area of the triangle is
Manish , 11 Years ago
Grade 12
Trigonometry> In a ?ABC, if cos A / a = cos B / b = cos...
1 Answers
bharat bajaj
cos A / a = cos B / b = cos C / c
cos A / (2R sin A) = cos B / (2R sin B) = cos C / (2R sin C)
cot A = cot B = cot C
A = B = C
?ABC is equilateral.
Area =
=
Thanks
cos A / (2R sin A) = cos B / (2R sin B) = cos C / (2R sin C)
cot A = cot B = cot C
A = B = C
?ABC is equilateral.
Area =
=Thanks
Bharat Bajaj
askiitians faculty
IIT Delhi
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