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The sides of a right angle triangle PQR are PQ=7cm; QR=25cm and angle P=90 degrees respectively.Then find.; tanQ - tanR.
Dear student Given In ∆PQR , PQ = 7 cm, QR = 25 cmBy Pythagoras theorem:PR² = QR² - PQ²= 25²- 7²= 625 - 49= 576PQ = 24Now,tanQ - tanR= PR/PQ - PQ/PR = 24/7 - 7/24 = 527/168
PQ = 7 cm, QR = 25 cmBy Pythagoras theorem:PR² = QR² - PQ²= 25²- 7²= 625 - 49= 576PQ = 24Now,tanQ - tanR= PR/PQ - PQ/PR = 24/7 - 7/24 = 527/168
Dear StudentGivenIn∆PQR,<P=90°,PQ=7cm,QR=25cmByPythagorastheorem:PR²=QR²-PQ²=25²-7²=625-49=576PR =24 cmNow,tanQ= 24/7tanR= 7/24tanQ - tanR = 24/7 –7/24 = (576-49)/168 =527/168Therefore,tanQ - tanR= 527/168Thanks
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