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The sides of a right angle triangle PQR are PQ=7cm; QR=25cm and angle P=90 degrees respectively.Then find.; tanQ - tanR. ​

The sides of a right angle triangle PQR are PQ=7cm; QR=25cm and angle P=90 degrees respectively.Then find.; tanQ - tanR.
​

Grade:10

2 Answers

Vikas TU
14149 Points
one year ago
Dear student 
Given In ∆PQR ,


PQ = 7 cm, QR = 25 cm
By Pythagoras theorem:
PR² = QR² - PQ²
= 25²- 7²
= 625 - 49
= 576
PQ = 24
Now,
tanQ - tanR
= PR/PQ - PQ/PR 
= 24/7 - 7/24 
= 527/168
 

Harshit Singh
askIITians Faculty 5965 Points
one year ago
Dear Student


GivenIn∆PQR,<P=90°,

PQ=7cm,QR=25cm

ByPythagorastheorem:

PR²=QR²-PQ²

=25²-7²

=625-49

=576

PR =24 cm

Now,

tanQ= 24/7
tanR= 7/24

tanQ - tanR = 24/7 –7/24
= (576-49)/168
=527/168

Therefore,
tanQ - tanR= 527/168

699-1129_061d6b073adc5751b7b7a254d1499fa9.jpg


Thanks

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