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If a+b+c=270 then find the value of sin2a-sin2b+sin2c

If a+b+c=270 then find the value of sin2a-sin2b+sin2c

Grade:11

1 Answers

Arun
25750 Points
4 years ago
Dear student
 
2 cos (A + B) sin (A – B) + 2 sinC cosC
 
 = 2 cos (270 – C) sin (A – B) + 2 sinC cosC
 = 2 sin C ( – sin (A – B) + cos (270 – ( A+B))
 = 2 sin C (  – sin ( A – B) – sin (A + B))
 = – 4 sinA sinB sinC
 

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