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In triangle ABC, show that sin 3A.cos 3 (B-C)+sin 3B.cos 3 (C-A)+sin 3C.cos 3 (A-B)=sin 3A. sin3B .sin3C

In triangle ABC, show that sin 3A.cos3(B-C)+sin 3B.cos3(C-A)+sin 3C.cos3(A-B)=sin 3A. sin3B .sin3C

Grade:10

1 Answers

Vikas Amritiya
askIITians Faculty 200 Points
3 months ago
Dear student please find attachment below 
Here is detailed solution of your doubts
keep asking ypur doubts
Askiitians faculty

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