Guest

In triangle ABC, show that sin 3A.cos 3 (B-C)+sin 3B.cos 3 (C-A)+sin 3C.cos 3 (A-B)=sin 3A. sin3B .sin3C

In triangle ABC, show that sin 3A.cos3(B-C)+sin 3B.cos3(C-A)+sin 3C.cos3(A-B)=sin 3A. sin3B .sin3C

Grade:10

1 Answers

Vikas Amritiya
askIITians Faculty 230 Points
2 years ago
Dear student please find attachment below 
Here is detailed solution of your doubts
keep asking ypur doubts
Askiitians faculty

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free