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if 420(tanA+cotA)=841 then what is value of (116cosA - 58sinA) if 420(tanA+cotA)=841 then what is value of (116cosA - 58sinA)
420(tanA+cotA)=841420(sinA/cosA +cosA/sinA) =841420/sinAcosA=841sin2A=840/841cos2A=sqrt of (1681/841)=41/841cosA=sqrt of (1+cos2A)/2=21/29sinA=sqrt of (1-cos2A)/2=20/29116cosA-58sinA=116(21/29)-58(20/29)=44Thanks & RegardsRinkoo GuptaAskIITians Faculty
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