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If A+B=90 then prove that (sinA+secA)/sinA=2tanAtanB If A+B=90 then prove that (sinA+secA)/sinA=2tanAtanB
the ques is wrong.RHS is always equal to 2 (bcoz tanA= cotB= 1/tanB so tanA.tanB= 1)But LHS is 1+1/sinAcosA= 1+2/sin2A which is not constant.hence recheck the ques and post along with a pic of the prob.KINDLY APPROVE :))
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