If sinA=B sin[A+2pie/3]=Csin[A+4pie/3].Prove that AB+BC+CA=0

Dear Vrushabh,

Dear vrushab,

 ???in this question there should be A multiplied to (SIN A)

it should be 

A SINA = B SIN[A+2PIE/3] = C SIN [A + 4 PIE/3]

PLS CHECK THE ATTACHED SOLUTION

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