Guest

If sinA=B sin[A+2pie/3]=Csin[A+4pie/3].Prove that AB+BC+CA=0

If sinA=B sin[A+2pie/3]=Csin[A+4pie/3].Prove that AB+BC+CA=0

Grade:9

1 Answers

jitender lakhanpal
62 Points
11 years ago

Dear Vrushabh,

 

Dear vrushab,

 ???in this question there should be A multiplied to (SIN A)

it should be 

A SINA = B SIN[A+2PIE/3] = C SIN [A + 4 PIE/3]

PLS CHECK THE ATTACHED SOLUTION

 

We are all IITians and here to help you in your IIT JEE preparation.

Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar : Click here to download the toolbar.. 

YOUR NAME 

 

 

We are all IITians and here to help you in your IIT JEE preparation.

Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar : Click here to download the toolbar.. 

JITENDER 

ASKIITIANS EXPERT

1234_36248_untitled.JPG

Think You Can Provide A Better Answer ?