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If sinA=B sin[A+2pie/3]=Csin[A+4pie/3].Prove that AB+BC+CA=0

If sinA=B sin[A+2pie/3]=Csin[A+4pie/3].Prove that AB+BC+CA=0

Grade:9

1 Answers

jitender lakhanpal
62 Points
10 years ago

Dear Vrushabh,

 

Dear vrushab,

 ???in this question there should be A multiplied to (SIN A)

it should be 

A SINA = B SIN[A+2PIE/3] = C SIN [A + 4 PIE/3]

PLS CHECK THE ATTACHED SOLUTION

 

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