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tanA=5/6 tanB=1/11 prove that A+B=45° solve the following tan65° cot165°
tan(a+b)= (tana+tanb)/(1 – tana*tanb)put values of tanA=5/6 tanB=1/11 to gettan(a+b)= 1 tan(a+b)= tan 45a+b= 45 now tan65° cot165°= tan65° cot(180 – 15°)= – tan65° cot15°= – tan65° tan(90 – 15°)= – tan65° tan75°. Note that it is only possible to calculate values trigonometric ratios for integral multiples of 1½ degree or 3 deg. so it is possible to calculate tan 75, but not tan 65. Hence the 2nd part of question is wrong and can not be calculated (except using a calci, which gives an approx value).
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