Please solve this question, this question is from calorimetery
Please solve this question, this question is from calorimetery
EnVae Tube , 6 Years ago
Grade 12th pass
Thermal Physics> Please solve this question, this question...
1 Answers
Arun
We know
heat loss =heat gain
maximum heat loss by copper block =mSdT
=2500g x 0.39jg-1k-1 x (500-0) k
=487,500 j
heat loss =heat gain
maximum heat loss by copper block =mSdT
=2500g x 0.39jg-1k-1 x (500-0) k
=487,500 j
now
487500 j=M L
where M is the mass of ice melted and L is latent heat of fusion .
487500 j =M x 335jg-1
M=1455.22 g =1.45522 Kg
487500 j=M L
where M is the mass of ice melted and L is latent heat of fusion .
487500 j =M x 335jg-1
M=1455.22 g =1.45522 Kg
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