A particle is projected at a speed u at angle theta with horizontal. At the highest point projectile split into two fragments of mass ratio 1;2 the smaller fragment coming to rest then the distance of heavier fragment from the point of projection is ?

Question

IPLKOMMADI 2017-18 · Answer

let the mass of the body be m THE POSITON OF C.O.M DOES NOT FOR INTERNAL CAUSES. As spliting into variuos parts is by internal cause it wont cause any change is position of c.o.m. SO if lets find it.

Sidharth · Answer

I think the answer is 9/4tines the actual range of the projectile apply conservation of momentum and see

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A particle is projected at a speed u at angle theta with horizontal. At the highest point projectile split into two fragments of mass ratio 1;2 the smaller fragment coming to rest then the distance of heavier fragment from the point of projection is ?

A particle is projected at a speed u at angle theta with horizontal. At the highest point projectile split into two fragments of mass ratio 1;2 the smaller fragment coming to rest then the distance of heavier fragment from the point of projection is ?

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A particle is projected at a speed u at angle theta with horizontal. At the highest point projectile split into two fragments of mass ratio 1;2 the smaller fragment coming to rest then the distance of heavier fragment from the point of projection is ?

A particle is projected at a speed u at angle theta with horizontal. At the highest point projectile split into two fragments of mass ratio 1;2 the smaller fragment coming to rest then the distance of heavier fragment from the point of projection is ?

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Most Scoring Topics in IIT JEE

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