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The maximum KE of photoelectrons emitted from a surface when photons of energy 6eV fall on it is 4eV. The stopping potential in volt is ? (Give solution with formula)

The maximum KE of photoelectrons emitted from a surface when photons of energy 6eV fall on it is 4eV. The stopping potential in volt is ? (Give solution with formula)

Grade:11

1 Answers

Adarsh
768 Points
6 years ago
Dear Preeti,
 
Stopping potential is the potential energy required to stop the movement of electron ..
In the above question 4eV is the energy from which the electrons are emitted and we require potential of 4V  to stop the motion of electron …  
 
After appling 4V, the potential energy of each electron will be 4ev and that is equal to K.E ,
So , – P.E = K.E hence no electron will move ..
 
Thanks and Regards
 Adarsh

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