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The initial number of atoms in a radioactive element is 6.0*10 raised to the power 20 and it's half life is 10 hours. Calculate the number of atoms which have decayed in 30hours and the amount of energy liberated if the energy liberated per atomic decay is 4.0*10 raised to the power-13

The initial number of atoms in a radioactive element is 6.0*10 raised to the power 20 and it's half life is 10 hours. Calculate the number of atoms which have decayed in 30hours and the amount of energy liberated if the energy liberated per atomic decay is 4.0*10 raised to the power-13

Grade:7

1 Answers

Yuvraj Singh
askIITians Faculty 75 Points
18 days ago
Que:
The initial number of atoms in a radioactive element is 6.0*10 raised to the power 20 and it's half life is 10 hours. Calculate the number of atoms which have decayed in 30hours and the amount of energy liberated if the energy liberated per atomic decay is 4.0*10 raised to the power-13


Ans:

N=Noe-at,,,,,so number of atoms decayed is
No-N,,,,and a=0.693/t
Total energy liberated = energy liberated by one atom×no.of atom decayed

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