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16gm Oxygen expand at constant pressure and 273.15 K to occupy double its original volume. The work done during process will be?

16gm Oxygen expand at constant pressure and 273.15 K to occupy double its original volume. The work done during process will be?

Grade:11

1 Answers

Satabdi das
13 Points
5 years ago
Since final volume is twice that of initial volume so 
W= P*(Vfinal-Vinitial) 
W=1*(2V-V)
W=V
Now no. Of moles = 16000/32= 500 
PV=nRT 
V=500*2*273=27300
Now W =27300/1000= 273kcal 
 

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