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```
16gm Oxygen expand at constant pressure and 273.15 K to occupy double its original volume. The work done during process will be?

```
3 years ago

Satabdi das
13 Points
```							Since final volume is twice that of initial volume so W= P*(Vfinal-Vinitial) W=1*(2V-V)W=VNow no. Of moles = 16000/32= 500 PV=nRT V=500*2*273=27300Now W =27300/1000= 273kcal
```
2 years ago
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