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A large heavy box is sliding without friction down a smooth inclined plane of inclination theta. from a point P on the bottom of the box particle is projected inside the box, with speed u(relative to box) at angle alpha with the bottom of the box. (a)Find the distance aling the bottom of the box between the point of projection P and the point Q where the particle lands. The particle does not hit any other surface of the box (b)If horizontal displacement of the particle w.r.t ground is zero.Find the speed of the box w.r.t the ground at the moment when particle was projected

A large heavy box is sliding without friction down a smooth inclined plane of inclination theta. from a point P on the bottom of the box  particle is projected inside the box, with speed u(relative to box) at angle alpha with the bottom of the box.


(a)Find the distance aling the bottom of the box between the point of projection P and the point Q where the particle lands. The particle does not hit any other surface of the box


(b)If horizontal displacement of the particle w.r.t ground is zero.Find the speed of the box w.r.t the ground at the moment when particle was projected

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1 Answers

Aman Bansal
592 Points
13 years ago

Dear Siddharth,

let perpendicular distance between bottom of box be y and let horizontal distance covered in box frame be x, let time duration of flight be 2usin(alpha)/gcos(theta)=t,

horizontal displacement w.r.t. box=x=ucos(alpha)t-((gsin(theta)t^2)/2),

let initial speed be v, zero displacement condition implies that speed of box w.r.t. INCLINED PLANE is such that

x=vt+((gt^2)sin(theta)/2)

Best Of luck

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