Grade 12Mechanics
1 Answer
vikas askiitian expert
Approved Tutor Answer15 Years agoconstan angular accleration = (alfa) (given)
w = wo + (alfa)t
w = (alfa)t (wo = 0)
normal reaction bw rod & ring is ma ... (a is linear accleration of rod at any time)
a = (alfa)r
N = m(alfa)r .......1
friction force (f) = uN = um(alfa)r ...............2
when this friction force is equal to centripital force then ring will slip
Fc(centripital force) = mw2r .........3
equatin 2 & 3
w2 = u(alfa) ...........4
w = (alfa)t so above eq becomes
(alfa)2t2 = u(alfa)
t2 = (u/alfa)
t = (u/alfa)1/2
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