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constan angular accleration = (alfa) (given) w = wo + (alfa)t w = (alfa)t (wo = 0) normal reaction bw rod & ring is ma ... (a is linear accleration of rod at any time) a = (alfa)r N = m(alfa)r .......1 friction force (f) = uN = um(alfa)r ...............2 when this friction force is equal to centripital force then ring will slip Fc(centripital force) = mw2r .........3 equatin 2 & 3 w2 = u(alfa) ...........4 w = (alfa)t so above eq becomes (alfa)2t2 = u(alfa) t2 = (u/alfa) t = (u/alfa)1/2
constan angular accleration = (alfa) (given)
w = wo + (alfa)t
w = (alfa)t (wo = 0)
normal reaction bw rod & ring is ma ... (a is linear accleration of rod at any time)
a = (alfa)r
N = m(alfa)r .......1
friction force (f) = uN = um(alfa)r ...............2
when this friction force is equal to centripital force then ring will slip
Fc(centripital force) = mw2r .........3
equatin 2 & 3
w2 = u(alfa) ...........4
w = (alfa)t so above eq becomes
(alfa)2t2 = u(alfa)
t2 = (u/alfa)
t = (u/alfa)1/2
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