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A block slides down an inclined plane of slope angle ? with constant velocity. It is then projected up the same plane with an initial velocity 'u' . How far up the incline will it move before coming to rest?

A block slides down an inclined plane of slope angle ? with constant velocity. It is then projected up the same plane with an initial velocity 'u' . How far up the incline will it move before coming to rest?

Grade:10

2 Answers

vikas askiitian expert
509 Points
10 years ago

block moves down the plane with constant velocity it means net force is zero...

force due to friction (f) = mgsin@                              (@ is the angle of plane)

net retardation force when body is projected upward is (f+mgsin@)

 f = mgsin@ so

net retardation force = 2mgsin@

     ma = mgsin@

     a(retardation) = 2gsin@        .............1

 V2 = U2 - 2aS

finally velocity becomes 0 so

  U2 = 2aS

 S = U2/2a

    =u2/4gsin@

Rishi Sharma
askIITians Faculty 646 Points
10 months ago
Dear Student,
Please find below the solution to your problem.

block moves down the plane with constant velocity it means net force is zero...
force due to friction (f) = mgsin@ (@ is the angle of plane)
net retardation force when body is projected upward is (f+mgsin@)
f = mgsin@ so
net retardation force = 2mgsin@
ma = mgsin@
a(retardation) = 2gsin@ .............1
V2 = U2 - 2aS
finally velocity becomes 0 so
U2 = 2aS
S = U2/2a
=u2/4gsin@

Thanks and Regards

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