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A ball after freely falling from a height of 4 . 9 m , hits a horizontal surface. If e = 3 / 4 , Then the ball will hit the surface, second time after ; a} 1sec b} 1.5sec c}2sec d}3sec

A ball after freely falling from a height of 4.9 m, hits a horizontal surface. If e=3/4, Then the ball will hit the surface, second time after ;    a} 1sec b} 1.5sec   c}2sec   d}3sec

Grade:11

1 Answers

Ayush Kumar
32 Points
one month ago
Hello dear
The question which you are asking is a bit related to kinematics and a bit related to collision
Just remeber some equations i.e.
Time period of an object=2u/g where u is the initial velocity
Velocity of an object when it reaches the ground9if it is going under free fall)=root under 2gh
e=velocity of seperation/velocity of approach
Now,
Velocity of approach =root under 2*9.8*4.9=9.8
e=3/4
Velocity of seperation=3/4*9.8
Time period=2*u/g
now u=velocity of seperation=3/4*9.8
T=2*3*9.8/4*9.8
T=1.5sec

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