Flag Integral Calculus> Please solve the question in the image at...
question mark

Please solve the question in the image attached
Answer of this question is Option 2

manjula reddy2222 , 6 Years ago
Grade
anser 1 Answers
Aditya Gupta
hello manjula, this ques can be easily solved  by drawing a graph of the 2 functions. further note that [x+1] can be written as [x] + 1 where [.] represents gif. (this follows from std properties of gif)
once you draw the graph, you ll notice that y= x^2 and y= [x] + 1 tend to meet at x=1. also, y= [x] + 1 is greater than x^2 when x is less than 1 but greater than 0.
so area bounded A= ∫ from 0 to 1 ([x] + 1 – x^2) dx
note that in x belonging to (0, 1), [x]= 0
so A= ∫ from 0 to 1 (1 – x^2) dx
= x – x^3/3 from 0 to 1
= 1 – 1/3
2/3
kindly approve :)
Last Activity: 6 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments