Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Find the area of bounded region f(x) =x^4_2x^2 and g(x) =2x^2
dear studentdy/dx = 4x^3 - 6x^2 + 2xfor maxima or minima; dy/dx=04x^3 - 6x^2 + 2x = 0x = 1, 1/2, 0d^2y/dx^2 = 12x^2 - 12x + 2at x = 0; d^2y/dx^2 = +veand at x = 1, 1/2; d^2y/dx^2 = -vetherefore point of minima = 1, 1/2Area= integration of y(x) from 1/2 ( lower limit ) to 1 ( upper limit)hope it helps
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -