∫(3x⁴+4x³/x⁴+x+1)²dx Find the solution in this type of question to related to intigration chapter

Question

Aditya Gupta · Answer

Multiply the numerator and denominator by x^-8 to convert the integrand into: (3x^-4+4x^-5)/(1+x^-3+x^-4)^2. Now simply substitute y= 1+x^-3+x^-4 so that dy= -(3x^-4+4x^-5)dx. After that you can easily integrate -y^-2 to get the final answer!

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∫(3x⁴+4x³/x⁴+x+1)²dx Find the solution in this type of question to related to intigration chapter

∫(3x⁴+4x³/x⁴+x+1)²dx

Find the solution in this type of question to related to intigration chapter

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