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  • ∫(3x⁴+4x³/x⁴+x+1)²dx
  • Find the solution in this type of question to related to intigration chapter

Rani , 4 Years ago
Grade 12
anser 1 Answers
Aditya Gupta

Last Activity: 4 Years ago

Multiply the numerator and denominator by x^-8 to convert the integrand into:
(3x^-4+4x^-5)/(1+x^-3+x^-4)^2.
Now simply substitute y= 1+x^-3+x^-4 so that dy= -(3x^-4+4x^-5)dx.
After that you can easily integrate -y^-2 to get the final answer!

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