Grade 12Integral CalculusIntegrate log(1/x – 1)upper limit =1lower limit=0 Suraj Chandramore 8 Years agoGrade 12
Arun8 Years agoDear Suraj log (1/(x-1)) = Log 1 - log (x-1) = 0 - log (x-1) Now integrate it by bypartsAnd then put limit RegardsArun (askIITians forum expert)
Rohit Sharma8 Years agolog(1/x-1)= log1-log(x-1)= 0-log(x-1)= -log(x-1)Then either integrate it by parts or you can substitute x-1 =t and then change the limits accordingly.