If n is a natural number, then exactly one of numbers n, n + 2 and n + 1 must be a multiple of

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Sathwik reddy · Answer

ans is 3 because let f(x) be x,x+1,x+2 f(n)=n,n+1,n+2 as one has to be multiple of some number it should not be in that so add them we get 3n+3 now we can take 3 as common and finally n,n+1,n+2 are multiples of 3

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If n is a natural number, then exactly one of numbers n, n + 2 and n + 1 must be a multiple of

If n is a natural number, then exactly one of numbers n, n + 2 and n + 1 must be a multiple of

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