Grade 9Integral Calculus
If n is a natural number, then exactly one of numbers n, n + 2 and n + 1 must be a multiple of
If n is a natural number, then exactly one of numbers n, n + 2 and n + 1 must be a multiple of
1 Answer
Sathwik reddy
ans is 3 because
let f(x) be x,x+1,x+2
f(n)=n,n+1,n+2
as one has to be multiple of some number
it should not be in that so add them we get 3n+3
now we can take 3 as common and finally n,n+1,n+2 are multiples of 3
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