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If a,b are roots of quadratic equation x^2+px+q=0 and c,d are roots of x^2+px-r=0 , then (a-c)(a-d) is equal to (A)q+r (B)q-r (C)-(q+r) (D)-(p+q+r)

```
2 years ago

Deepak Kumar Shringi
4402 Points
```							as a is root of equation (i) it will satisfy it soa2+ap+q=0a2+ap=-q....(A)c+d=-p....(I)cd=-r..(ii)(a-c)(a-d)=a2-(c+d)a+cd {now use (i) & (ii)}=a2+ap-r {now use (A)}=-q-r   option C is correct
```
2 years ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions