For the ellipse (x+y-1)^2 /9+(x-y+2)^2/4 =1 Ends of minor axis are

Question

Arun · Answer

Dear students first find centre of ellipse and then we know b = 2 hence use parametric points to find end points however these typebof ellipse is not in syllabus

Vikas TU · Answer

Der student Please follow the below link https://www.askiitians.com/revision-notes-new/maths/ellipse.html Good Luck

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For the ellipse (x+y-1)^2 /9+(x-y+2)^2/4 =1 Ends of minor axis are

For the ellipse (x+y-1)^2 /9+(x-y+2)^2/4 =1

Ends of minor axis are

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For the ellipse (x+y-1)^2 /9+(x-y+2)^2/4 =1 Ends of minor axis are

For the ellipse (x+y-1)^2 /9+(x-y+2)^2/4 =1 Ends of minor axis are

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For the ellipse (x+y-1)^2 /9+(x-y+2)^2/4 =1

Ends of minor axis are