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`        A stone tied to a string of length L is whirled in a vertical circle and other end of a string is at the centre. at a certain instant of time, the stone is at its highest position, and has a speed u. The magnitude of change in the velocity has it reaches a position where string is horizontal is `
one year ago

Arun
23013 Points
```							Dear student  The portion of Velocity change –change in velocity = v jcap – u icapand the magnitude of change in velocity =>whole uder-root ( Vsquare + U square + 2 * V * U * Cos90 )=> whole under-root (Vsquare+Usquare +0 )                           (as cos90 = 0)=> whole under-root (Vsquare+Usquare)  So, we have to find the value of (Vsquare+Usquare) ,i.e., whole under-root   [2*{U square – gl }] Regards Arun
```
one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions