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If a vector OP = 3i+3j is turned clockwise by an angle of 15 degree, then the y component of rotated vector would be... [I need solution of this question with full explanation.]
Vector OP is given as OP =3i+3jNow we can find it's magnitude as well as it's direction bothMagnitude =√3^2+√3^2 =3√2Now in order to find the direction Theeta=tan^-1(3/3) =45°Now when vector is rotated by 15° it's magnitude will remain unchanged While angle of vector will become 45+15=60°So y component = Y=OP sin60° =3√2 =3.67Answerd by Kapil paliwal
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