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Find value of: Integration of 1/x^2 dx with upper limit b and lower limit a.
Hi 1/(x^2) can be written as x^(-2) And we know that the formula of integration for x^n (where n is not equal to -1) wrt x = (x^ (n+1)) / (n+1) In our case, n = -2 Hence, the integration will give us (x^ (-1)) / (-1) = -1/x the upper and lower limits are given as b and a This implies, integration = -1/b - (-1/a) = 1/a - 1/b
Hi
1/(x^2) can be written as x^(-2)
And we know that the formula of integration for x^n (where n is not equal to -1) wrt x = (x^ (n+1)) / (n+1)
In our case, n = -2 Hence, the integration will give us (x^ (-1)) / (-1) = -1/x the upper and lower limits are given as b and a
This implies, integration = -1/b - (-1/a) = 1/a - 1/b
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