The equation of the chord of the circle x2 + y2 – 4x = 0 whose mid point is (1, 0) is
(A) y = 2 (B) y = 1 (C) x = 2 (D) x = 1

Question

The equation of the chord of the circle x2 + y2 – 4x = 0 whose mid point is (1, 0) is (A) y = 2 (B) y = 1 (C) x = 2 (D) x = 1

Arun · Answer

Dear student Use T = S1 x – 2 (x + 1) = 1- 4 – x – 2 = – 3 x = 1 Hence option D is correct Thanks and regards

Vikas TU · Answer

The equation of the chord is x×1+0×y−2(x+1)=1+0−4 [ Using T=S1] ⇒−x−2=−3 ⇒x=1 …...............................................

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The equation of the chord of the circle x2 + y2 – 4x = 0 whose mid point is (1, 0) is (A) y = 2 (B) y = 1 (C) x = 2 (D) x = 1

The equation of the chord of the circle x2 + y2 – 4x = 0 whose mid point is (1, 0) is
(A) y = 2 (B) y = 1 (C) x = 2 (D) x = 1

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The equation of the chord of the circle x2 + y2 – 4x = 0 whose mid point is (1, 0) is (A) y = 2 (B) y = 1 (C) x = 2 (D) x = 1

The equation of the chord of the circle x2 + y2 – 4x = 0 whose mid point is (1, 0) is (A) y = 2 (B) y = 1 (C) x = 2 (D) x = 1

2 Answers

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The equation of the chord of the circle x2 + y2 – 4x = 0 whose mid point is (1, 0) is
(A) y = 2 (B) y = 1 (C) x = 2 (D) x = 1