Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping

It is a question of limit. Please find the answer and send me. I am very thankful for the help.

It is a question of limit. Please find the answer and send me. I am very thankful for the help.

Question Image
Grade:12

1 Answers

abhishek
39 Points
one year ago
As you can see it is 0/0 form of indetermency. 
Hence apply l hopitals stepwise
Finally you will get answer.  
Look at below\lim _{x \rightarrow 0} \frac{1}{x}\left[n^{2}-\left(\frac{1}{1^{x}}+\frac{1}{2^{x}}+\cdots \cdots+\frac{1}{n x}\right)^{2}\right] \frac{0}{0} form : Apply L- tiopital Pube \lim _{x \rightarrow 0}\left(0-2\left(\frac{1}{1^{x}}+\frac{1}{2^{x}}+\cdots+\frac{1}{n^{x}}\right) \cdot\left(1^{-x}(-1) \ln 1+2^{-x}(-1) \ln 2\right.\right. \left.n^{-x}(-1) \ln n\right) \Rightarrow 2 n \cdot \ln (n !) \Rightarrow \ln(n))^{2 n}

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Engineering Entrance Exams

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Register ICAT

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More