MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
Formula for the force of attraction between two parallelmoving protons
one year ago

Answers : (1)

Rajdeep
231 Points
							
HEY THERE!
 
Here’s the general formula:
 
\small F = k_{e}\frac{q_{1}q_{2}}{r^{2}}\\\\ k_{e} = 8.99 \times 10^{9} Nm^{2}C^{-2}
 
Where, \small q_{1}, q_{2} are the charges of proton (both are same, = +1.6 x 10-19 C) and r is the distance between the two parallel moving protons.
 
So, we have :
 
\small F = 8.99\times 10^{9} \times \frac{(1.6\times 10^{-19})^{2}}{r^{2}} \\\\= \frac{2.301\times10^{-28}}{r^{2}}
 
THANKS!
9 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details