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In a closed organ pipe the fundamental frequency is n. what will be the ratio of frequencies of the next three overtones? (a) 2: 3: 4 (b) 3: 4: 5 (c) 3: 7: 11 (d) 3: 5: 7

In a closed organ pipe the fundamental frequency is n. what will be the ratio of frequencies of the next three overtones?
(a) 2: 3: 4
(b) 3: 4: 5
(c) 3: 7: 11
(d) 3: 5: 7

Grade:Upto college level

2 Answers

Arun
25763 Points
one year ago
In a closed organ pipe the fundamental frequency is n. the ratio of frequencies of the next three overtones  will be in 3:5:7
hence option D iw correct
Vikas TU
14149 Points
one year ago
frequency of xth normal mode of vibration of closed organ pipe is given by ,
nx = (2x−1)n ,         x=1,2,3............ ,
it is (x−1)th overtone ,
given that fundamental frequency is n1=n ,
therefore , first overtone frequency  for x=2, n2 =3n ,
second overtone frequency  for x=3, n3=5n ,
 third overtone frequency  for x=4, n4=7n ,
hence ratio of next three fequencies is ,
           n2:n3:n4 = 3:5:7

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