Grade 12Electrostatics

Two point charges repels each other with a force F when placed in water of dielectric constant 81.what will the force between them when placed the same distance apart in air

Priyanka

10 Years agoGrade 12

2 Answers

Aamina

10 Years ago

If some dielectric is present in the space between the charges, the net force acting on each charge is altered becuse charges are induced in the molecules of the intervening medium the force decreases K times.

F= 1 q₁q₂ (in vacuum )

4 $\tiny \prod$ $\small \varepsilon$ ₀ r²

F^’= 1 . q₁q₂ (in medium)

4 $\tiny \prod$ $\varepsilon$ ₀k r²

K is dielectric constant.

Hope this helps you.

Abhinav Singh

9 Years ago

Dielectric constant of water.k=81F(air)=1/4pie epsilon×q1q2/r2(square)F (water)=1/4pie epsilon k (dielectric constant)×q1q2/r2 (square)F (water)=1/81×1/4pie epsilon ×q1q2/r2 (square)F (water)=1/81×F (air)Therefore:F (air)=81 F (water).ans.