#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Two point charges repels each other with a force F when placed in water of dielectric constant 81.what will the force between them when placed the same distance apart in air

Aamina
64 Points
5 years ago
If some dielectric is present in the space between the charges, the net force acting on each charge is altered becuse charges are induced in the molecules of the intervening medium the force decreases K times.

F=   1    q1q                                           (in vacuum )
4$\tiny \prod$$\small \varepsilon$0  r2

F=      1     . q1q2                                         (in medium)
4$\tiny \prod$$\varepsilon$0k     r2

K is dielectric constant.
Hope this helps you.

Abhinav Singh
11 Points
4 years ago
Dielectric constant of water.k=81F(air)=1/4pie epsilon×q1q2/r2(square)F (water)=1/4pie epsilon k (dielectric constant)×q1q2/r2 (square)F (water)=1/81×1/4pie epsilon ×q1q2/r2 (square)F (water)=1/81×F (air)Therefore:F (air)=81 F (water).ans.