# NaCl molecule is bound due to the electric force between the sodium and the chlorine ions when one electron of sodium if transferred to chlorine. Taking the separation between the ions to be 2.75×10^(-8) cm, find the force of attraction between them. State the assumptions (if any) that you have made.

Arun
25750 Points
6 years ago
r=2.75×10^-8×10^-2 So,r=2.75×10^-10F=1/4piepsnot×q1q2/r^2F=9×10^-9×1.6×10^-19×1.6×10-19/(2.75×10^-10)^2F=9×10^9×1.6×1.6×10^-38×10-20/2.75×2.75F=9×1.6×1.6×10^29-38/2.75×2.75F=9×1.6×1.6×10^-9/2.75×2.75F=23.04/7.56×10^-9So,F=3.04×10-9 NewtonWe have take one one charge of na and cl because it is mentioned in the question that one electron of sodium is transferred to chlorine So, Na=10electron 11 proton Cl=18 electron 17 protonSo,Na and Cl have one charge
Gitanjali Rout
184 Points
6 years ago
Tr=2.75×10^-8×10^-2 So,r=2.75×10^-10F=1/4piepsnot×q1q2/r^2F=9×10^-9×1.6×10^-19×1.6×10-19/(2.75×10^-10)^2F=9×10^9×1.6×1.6×10^-38×10-20/2.75×2.75F=9×1.6×1.6×10^29-38/2.75×2.75F=9×1.6×1.6×10^-9/2.75×2.75F=23.04/7.56×10^-9So,F=3.04×10-9 NewtonWe have take one one charge of na and cl because it is mentioned in the question that one electron of sodium is transferred to chlorine So, Na=10electron 11 proton Cl=18 electron 17 protonSo,Na and Cl have one charg

Forum Team
94 Points
6 years ago
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Forum Team