Two equal charges are separated by a distance d .

Question

Two equal charges are separated by a distance d . A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force

Anushree Sharma · Accepted Answer

As cos component cancel each other, sin components of force add up. We can find the maxima of the equation to find the place of maximum value of force.2F sinQ = 2 Kq2 sinQ r2 + d2 4 Put d ( 2F sinQ) = 0 dxWe getd (2kq2. × X. dx ( x2 + d2 √ x2. +. d2 4. ( 4) = 2kq2 +. 2kq2. × (-3 ) x (x2. +. d2. )3/2. ( x2. d​2. )3/2 2 4. 4 On solving we get, x2 + d2 = 3x2 4 Through this equation,We get, X= d 2√2

Electrostatics> Two equal charges are separated by a dist...

Two equal charges are separated by a distance d . A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force

saquib dayan , 4 Years ago

Anushree Sharma

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Electrostatics> Two equal charges are separated by a dist...

Two equal charges are separated by a distance d . A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force

saquib dayan , 4 Years ago

Anushree Sharma

LIVE ONLINE CLASSES

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