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Two equal charges are separated by a distance d . A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force

Two equal charges are separated by a distance d . A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force

Grade:8

1 Answers

Anushree Sharma
14 Points
10 months ago
As cos component cancel each other, sin components of force add up. We can find the maxima of the equation to find the place of maximum value of force.
2F sinQ = 2 Kq2      sinQ
                   r2 + d2
                                4
 
Put d ( 2F sinQ)  = 0
             dx
We get
d   (2kq2.       ×      X.           
dx  ( x2 + d2     √   x2.  +.  d2                     
               4.          (  4) 
 
= 2kq2               +.     2kq2.                       ×   (-3 ) x
    (x2. +. d2)3/2.        (  x2.   d​2.     )3/2            2
                 4.                                4
 
On solving we get, 
x2 + d2       = 3x2
          4
  Through this equation,
We get,
             X= d  
                   2√2
 
 

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