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`        a²/(b+c) + b²/(c+a) + c²/(a+b)  = 0.Prove that a/(b+c) + b/(c+a) + c/(a+b) = 1. `
9 months ago

Arun
22572 Points
```							 Dear student take a/(b+c) +b/(c+a) +c/(a+b) =1 then multiply (a+b+c)  in both the sidesa(a+b+c) / (b+c) + b(a+b+c) / (a+c) + c(a+b+c) / (b+a) = a+b+c a2 / (b+c)  + a(b+c)/ (b+c)  + b2 / (c+a) + b(c+a)/ (c+a)  +  c2 / (a+b)  + c(a+b)/ (a+b) = a+b+c a2 / (b+c)  + a + b2 / (c+a) + b  +  c2 / (a+b)  + c = a+b+c a2 / (b+c)  + b2 / (c+a) +  c2 / (a+b)  = 0 hope it helps
```
9 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions