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Find the range of value of p for x^2-px+p+3 has one positive and one negative root
one month ago

Answers : (3)

Vikas TU
9105 Points
							
x^2-px+p+3 is the given quadratic equation. 
To have one positive and one negative root product of the root will be negative.
p+3
p 
Hope this helps 
Good Luck 
one month ago
Vikas TU
9105 Points
							
Hiii dear , 
The ans of the above question is p+3
so, p
Hope this helps 
Good Luuuck 
one month ago
Aditya Gupta
1690 Points
							
note that the function f(x)= x^2-px+p+3 will have one positive and one negative root if and only if f(0) is less than 0 (since a= 1 is greater than zero) due to application of continuity of f and f( – infinity)= f(infinity)= infinity.
so, f(0)= p+3 should be less than 0
or p belongs to ( – infinity, – 3).
kindly approve :=)
one month ago
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